10h^2+13h-30=0

Solution for 10h^2+13h-30=0 equation:

10h^2+13h-30=0

a = 10; b = 13; c = -30;
Δ = b2-4ac
Δ = 132-4·10·(-30)
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1369}=37$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-37}{2*10}=\frac{-50}{20}
=-2+1/2
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+37}{2*10}=\frac{24}{20}
=1+1/5
$